8n^2-3n=0

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Solution for 8n^2-3n=0 equation: 



8n^2-3n=0

a = 8; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·8·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*8}=\frac{0}{16}
=0
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*8}=\frac{6}{16}
=3/8
$

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